Here we'll use & operator to find thae number is Odd or Even.

```
public class JavaOneWorld {
public static void main(String
args[]) {
int x= 7;
if((x&1)==0){
System.out.println("even");
}else{
System.out.println("odd");
}
}
}
```

The idea behind using the & operator !!!!!

As we already know binary works only on 1 and 0.

and a number is either odd or even,

so if a number is even then the last bit of that number must be 0 and if odd then the last bit must be 1.

i.e.-

5 odd

101 last bit is 1.

4 even

100 last bit is 0.

so here we have to use this property to find out the odd/even

Deep dive in this post...

https://www.javaoneworld.com/2021/05/find-odd-even-using-bitwise-operator.html?m=1

## Discussion (0)